Ginger91 195 Posted September 28, 2016 Share Posted September 28, 2016 I don't know who to do this problem. Please help. And include the work too because my teachers really anal about including work and cancellation. Thank you~ A student wants to make a 1.5M solution of ammonium chloride. If he has 50g, what volume of a solution can he make? Link to comment Share on other sites More sharing options...
angy 5,950 Posted September 28, 2016 Share Posted September 28, 2016 That M in 1.5M stands for mole, right? I'll try to solve it, but my chemistry might be broken lol Link to comment Share on other sites More sharing options...
Goten21 2,501 Posted September 28, 2016 Share Posted September 28, 2016 That M in 1.5M stands for mole, right? I'll try to solve it, but my chemistry might be broken lol it stands for molarity, aka mole per litre I think Link to comment Share on other sites More sharing options...
angy 5,950 Posted September 28, 2016 Share Posted September 28, 2016 it stands for molarity, aka mole per litre I think Oh, then it gets easier Isn't the answer 0.62L? Link to comment Share on other sites More sharing options...
angy 5,950 Posted September 28, 2016 Share Posted September 28, 2016 I don't know if it's right but I did: M(NH4Cl)= 53.5 g/mol n=m/M n=50/53.5 = 0.93 mol 1L------ 1.5mol x--------0.93 mol x= 0.93/1.5= 0.62 Link to comment Share on other sites More sharing options...
Goten21 2,501 Posted September 28, 2016 Share Posted September 28, 2016 I think it's this: Find out what the formula for ammonium chloride is. Look up what their moleculair weights are. We'll call that X. If you have one mole of that, you have X g You actually have 50g. 50 / X is the amount of mole you have 50 / X ------- = 1.5M ?L 50 / X ------- = answer 1.5 Link to comment Share on other sites More sharing options...
Goten21 2,501 Posted September 28, 2016 Share Posted September 28, 2016 I don't know if it's right but I did: M(NH4Cl)= 53.5 g/mol n=m/M n=50/53.5 = 0.93 mol 1L------ 1.5mol x--------0.93 mol x= 0.93/1.5= 0.62 We did the same thing basically so I'm sure it's this ^^ Link to comment Share on other sites More sharing options...
Ginger91 195 Posted September 28, 2016 Author Share Posted September 28, 2016 Thanks guys~ Link to comment Share on other sites More sharing options...
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