The Official Homework Help Thread!

[Guardian of the Galaxy]

Helpppp please
Can you solve for a? Idk why it wont work
I tried using the method i used for previous questions and got them right, idk why it aint working now :'(
(2a -1)^2 - (a - 3)(a + 3) = 3a(a- 1)

 

Expanding and evaluating:

(2a -1)^2 - (a - 3)(a + 3) = 3a(a- 1)
4a^2 - 4a + 1 - (a^2 - 9) = 3a^2 - 3a

4a^2 - 4a + 1 - a^2 + 9 = 3a^2 - 3a

Moving all the terms to the same side, combine terms of the same order (exponent)

(4 a^2 - 3a^2 - a^2) - 4a + 3a + 1 + 9 = 0

-a + 10 = 0

a = 10

 

Check:

Left side:

(2*10 - 1)^2 - (10 - 3)(10 + 3)

= (20 - 1)^2 - (7)(13)

= 19^2 - 91

= 361 - 91

= 270

 

Right side:

3(10)(10 - 1)

= 30(9)

= 270

Edited October 5, 2015 by a232313

[aiyuu]

help please T_T I

 

A train travels 39 metres, 37 metres, 37 metres in each of 3 consecutive seconds along a straight railway track. Show that thi sis consistent with motion under constant deceleration.

Find how much further the train will travel before coming to rest.

[Aquashakencola]

HELP

I have a math test tomorrow :rlytearpls:

[oh-gumdrop]

i see what i forgot to do now, thank youuuu Edited October 6, 2015 by koo

[ErikaEGO]

HELP

I have a math test tomorrow :rlytearpls:

 

For the first one, just plug in the distance between their houses as x, so like

 

C=  $ 0.25 ( 6 ) + $10

 

 and then, just add the money together and you'll find how much the ride costs. :meow:

 

I have no idea about the 2nd one though, I'll quote you later if I do though , sorry  :blush:

[pimo]

help please T_T I

A train travels 39 metres, 37 metres, 37 metres in each of 3 consecutive seconds along a straight railway track. Show that thi sis consistent with motion under constant deceleration.
Find how much further the train will travel before coming to rest.

are you sure u posted the question right? I think that last distance might be different (I think it should be 35), if not, I'm really stumped sorry :( Edited October 6, 2015 by pimo

[Guardian of the Galaxy]

HELP

I have a math test tomorrow :rlytearpls:

 

6.

As it turns out they set the question up perfectly for you. If you want to know how they got those numbers:

 

Right hand side:

0.05(200) - this is how much butterfat you have in total. 200 L of cream-milk mix with 5% fat.

 

Left hand side:

0.03x - this is how much butterfat is coming from milk. x L of milk at 3% fat

0.1(200 - x) - this is how much butterfat is coming from cream. (200 - x) L of cream at 10% fat.

 

You want to find the amount of milk (x) and the amount of cream (200 - x)

 

0.03x + 0.1(200 - x) = 0.05(200)
- multiply the 0.1 into the bracket by distributing

0.03x + 20 - 0.1x = 10

-0.07x = -10

x = (-10/-0.07)

x = 1000/7 (approximately 142.86 L)

 

The amount of cream is 200 - x

200 - x = 400/7 (approximately 57.14 L)

[Theoneandonly]

what i never knew there was such  thread like this!!!  

[VANTE]

what i never knew there was such  thread like this!!!  

join us in our misery  :ohpressor:

[aiyuu]

are you sure u posted the question right? I think that last distance might be different (I think it should be 35), if not, I'm really stumped sorry :(

yes you're right! It's supposed to be 35 sorry. I managed to find the constant deceleration but the last part I'm stuck on..

[Athena]

I need help finding something to do a current event on. My govt teacher assigned "open government" as the topic for the last current event and I already had so much difficulty searching for an article. But now we have to do another one on the same topic. Any suggestions? It has to be US-centric though. For my last one I did a report about the new government college scoreboard website.

Edited October 6, 2015 by Athena

[VANTE]

I need help finding something to do a current event on. My govt teacher assigned "open government" as the topic for the last current event and I already had so much difficulty searching for an article. But now we have to do another one on the same topic. Any suggestions? It has to be US-centric though. For my last one I did a report about the new government college scoreboard website.

how about http://bigstory.ap.org/article/b6e5b41255a944e480a33e1330d2a95e/security-increased-around-oklahoma-ten-commandments

Does that work?

[Athena]

how about http://bigstory.ap.org/article/b6e5b41255a944e480a33e1330d2a95e/security-increased-around-oklahoma-ten-commandments

Does that work?

I actually need the article to be from at least a couple of days ago. Since it's due tomorrow. :lol:

[VANTE]

I actually need the article to be from at least a couple of days ago. Since it's due tomorrow. :lol:

hahaha no prob, I'll try to find another one

[VANTE]

How this?

http://www.charlotteobserver.com/news/local/article36967686.html

[Athena]

How this?

http://www.charlotteobserver.com/news/local/article36967686.html

Thank you!

[VANTE]

Thank you!

no problem! I'm just glad it wasn't math this time lol

[Theoneandonly]

how about http://bigstory.ap.org/article/b6e5b41255a944e480a33e1330d2a95e/security-increased-around-oklahoma-ten-commandments

Does that work?

 

 

 i might need this article for my ap gov class. you mind if i use it?

[pimo]

watch ailees new song on youtube :) 

(dp)

Edited October 6, 2015 by pimo

[pimo]

yes you're right! It's supposed to be 35 sorry. I managed to find the constant deceleration but the last part I'm stuck on..

ok makes more sense now lol :lol:

Im not sure, is this a math or physics question?

do you know the answer btw?

I think you may have to use one of these equations

Edited October 6, 2015 by pimo

[aiyuu]

ok makes more sense now lol :lol:

Im not sure, is this a math or physics question?

do you know the answer btw?

I think you may have to use one of these equations

I don't know what you'd call it, where I study it's called Applied Maths. It's kind of the maths used in engineering, physics, science etc. Thank you for these equations tho, the teacher only gave me 3, I haven't seen these ones. I'm afraid I don't know the answer either :/

[VANTE]

 i might need this article for my ap gov class. you mind if i use it?

go for it!

[pimo]

I don't know what you'd call it, where I study it's called Applied Maths. It's kind of the maths used in engineering, physics, science etc. Thank you for these equations tho, the teacher only gave me 3, I haven't seen these ones. I'm afraid I don't know the answer either :/

I was wondering if there was an answer because Im not sure if the way I'm thinking of solving it is right
[Spoiler] since they're asking for the distance the train travels after the third second until its at rest, I'd think you make Vi = 35m/s (speed of the train at 3 seconds), Vf = 0 (rest), and a = -2. Then I'd use the fourth equation and solve for d.
I got 306.25 for d [/spoiler]

[duckduckhorse]

This isn't a typical request for help, but I figured it would fit the best in this thread compared to elsewhere on OH.

 

I'm looking for U.S. undergraduate college students willing to spare a minute to fill out this survey that I've created for a statistics class. There are only five questions, so it literally shouldn't take you more than a couple minutes. I'd appreciate all the help that I can get!

Survey link: https://sjsu.qualtrics.com//SE/?SID=SV_ebV4BGYsuSXauZ7

[VANTE]

This isn't a typical request for help, but I figured it would fit the best in this thread compared to elsewhere on OH.

 

I'm looking for U.S. undergraduate college students willing to spare a minute to fill out this survey that I've created for a statistics class. There are only five questions, so it literally shouldn't take you more than a couple minutes. I'd appreciate all the help that I can get!

Survey link: https://sjsu.qualtrics.com//SE/?SID=SV_ebV4BGYsuSXauZ7

Done!  :ohbi: