The Official Homework Help Thread!

[Athena]

i would've said that 2400 has 4 significative figures but then where i live we'd never write "6." (we don't even use decimal points we use commas)
because if you measure or calculate something and say that the result is 2400 then it means that you're sure that there are two zeros after your 24, or at least that's what i've always learned
a rigorous way of writing it with 2 significant figures would be "2.4*10^3" i think?? i'm gonna need someone to correct me if i'm wrong

i'm curious now, where are you from?? because maybe the difference comes from country conventions

The US. "6." was just an example. Nobody really uses it in everyday life but I've seen teachers use something similar when they do problems.

[TZUYODA]

Hello~ I just wanted this checked :) it's just sig-fig practice but its on webassign and if I mess up, it'll grade it right away ;_; i don't want c's

 

(a) 11560 

1.5 x 10^4
(b) 0.00218 
2.18 x 10^3
(c) 6.8 
6.8 x 10^0
(d) 2763500 
2.76 x 10 ^6
(e) 0.0219 
2.19 x 10^2
(f) 0.00000444 
4.44 x 10^6

 

that's all~ thank you :) i just wanna know if any is wrong before submitting the work ;D

 

EDIT: also if anyone knows latin, that'd be really helpful too cuz i need help with my latin hw :D

Edited September 17, 2015 by Milk Choco

[siwan]

Hello~ I just wanted this checked :) it's just sig-fig practice but its on webassign and if I mess up, it'll grade it right away ;_; i don't want c's

 

(a) 11560 

1.5 x 10^4
(b) 0.00218 
2.18 x 10^3
(c) 6.8 
6.8 x 10^0
(d) 2763500 
2.76 x 10 ^6
(e) 0.0219 
2.19 x 10^2
(f) 0.00000444 
4.44 x 10^6

 

that's all~ thank you :) i just wanna know if any is wrong before submitting the work ;D

 

EDIT: also if anyone knows latin, that'd be really helpful too cuz i need help with my latin hw :D

 

did you forget some negative signs

 

also your first one is wrong lol it should be 1.2*10^4 or 1.16*10^4 depending on the sf

Edited September 17, 2015 by kamiprune

[AfterglowVape]

any ACCA kids around?  :imstupid:

[TZUYODA]

did you forget some negative signs

 

also your first one is wrong lol it should be 1.2*10^4 or 1.16*10^4 depending on the sf

 

no i didnt forget any  OH FUCK I FORGOT ABOUT THE DECIMALS THANK YOU

 

yeah, i forgot to put in a digit there ;_; 

Edited September 17, 2015 by Milk Choco

[siwan]

no i didnt forget any  OH FUCK I FORGOT ABOUT THE DECIMALS THANK YOU

 

yeah, i forgot to put in a digit there ;_; 

 

is everything supposed to be 3sf? if it is, c should be 6.80 (i dont think you need the exponent)

Edited September 17, 2015 by kamiprune

[TZUYODA]

is everything supposed to be 3sf? if it is, c should be 6.80 (i dont think you need the exponent)

 

no the zero would just be a place holder.

i think a would be 1.156 because the zero is also just a place holder

but i'm scared to submit it cuz i dun wanna get them wrong lol

[VANTE]

any ACCA kids around?  :imstupid:

whats that?

[AfterglowVape]

whats that?

Association of Chartered Certified Accountants  :imstupid: 

[VANTE]

Association of Chartered Certified Accountants  :imstupid: 

oh lol nope sorry  :imstupid:

[siwan]

no the zero would just be a place holder.

i think a would be 1.156 because the zero is also just a place holder

but i'm scared to submit it cuz i dun wanna get them wrong lol

 

lol what is the question asking you to do? does it state the amount of significant figures? if it doesn't i doubt it matters (tho convention is probably 3)

[TZUYODA]

lol what is the question asking you to do? does it state the amount of significant figures? if it doesn't i doubt it matters (tho convention is probably 3)

 

no it's just asking you to rewrite it using significant figures ._.

[Athena]

Hello~ I just wanted this checked :) it's just sig-fig practice but its on webassign and if I mess up, it'll grade it right away ;_; i don't want c's

 

(a) 11560 

1.5 x 10^4
(b) 0.00218 
2.18 x 10^3
(c) 6.8 
6.8 x 10^0
(d) 2763500 
2.76 x 10 ^6
(e) 0.0219 
2.19 x 10^2
(f) 0.00000444 
4.44 x 10^6

 

that's all~ thank you :) i just wanna know if any is wrong before submitting the work ;D

 

EDIT: also if anyone knows latin, that'd be really helpful too cuz i need help with my latin hw :D

Your answers for b, e, and f should be negative exponents not positive.

 

I think it is this:

a. 1.156 x 10^4

b. 2.18 x 10^-3

c. 6.8 x 10^0

d. 2.7635 x 10^6

e. 2.19 x 10^-2

f. 4.44 x 10^-6

[siwan]

no it's just asking you to rewrite it using significant figures ._.

 

huh

 

so it doesn't state the amount of significant figures? then how would you know how many digits you need lol

 

and if it's not asking for standard form then why do you even need exponents? why can't you use 11600 (3sf) rather than 1.156*10^4?

 

sry im confused

Edited September 17, 2015 by kamiprune

[TZUYODA]

huh

 

so it doesn't state the amount of significant figures? then how would you know how many digits you need lol

 

and if it's not asking for standard form then why do you even need exponents? why can't you use 11600 (3sf) rather than 1.156*10^4?

 

sry im confused

 

I have no idea ;_; i think because the zero in 11560 is insignificant, that's why it isn't included or something ;_; i dun understand webassign, it rejected a lot of the answers I put in ._.

 

Your answers for b, e, and f should be negative exponents not positive.

 

I think it is this:

a. 1.156 x 10^4

b. 2.18 x 10^-3

c. 6.8 x 10^0

d. 2.7635 x 10^6

e. 2.19 x 10^-2

f. 4.44 x 10^-6

 

thanks! Wish I saw this sooner because I submitted already and got 69% ;_; there were more questions that I flopped on ;_;

[siwan]

I have no idea ;_; i think because the zero in 11560 is insignificant, that's why it isn't included or something ;_; i dun understand webassign, it rejected a lot of the answers I put in ._.

 

hm

 

dont worry too much lol as long as you understand the concept of significant figures that's all that matters tbh

 

online grading methods that have strictly prescriptive lists of answers arent the best so w/e

Edited September 17, 2015 by kamiprune

[BAP_STARLIGHT]

Can someone help me? I have no idea what I'm doing. Can someone show me the work and explain it to me?

1. A parking garage charges $1.50 for the first hour and $0.75 per hour for each additional hour or part of an hour. How many dollars will it cost Bill to park in the garage for 5 1/2 hours. 

 

2. Given f(x) = x^2+2x+1/x^2-1 , find f(2)/f(0)

 

3. Vick's Video offers two different membership plans. One plan has a $25 annual membership fee and it cost $1.50 each to rent videos. The other plan has no membership fee but it cost $3 per video rental. What is the fewest numbers of videos Sam can rent in one year for which the first plan is the least expensive.

[pimo]

Can someone help me? I have no idea what I'm doing. Can someone show me the work and explain it to me?
1. A parking garage charges $1.50 for the first hour and $0.75 per hour for each additional hour or part of an hour. How many dollars will it cost Bill to park in the garage for 5 1/2 hours.

2. Given f(x) = x^2+2x+1/x^2-1 , find f(2)/f(0)

3. Vick's Video offers two different membership plans. One plan has a $25 annual membership fee and it cost $1.50 each to rent videos. The other plan has no membership fee but it cost $3 per video rental. What is the fewest numbers of videos Sam can rent in one year for which the first plan is the least expensive.

nvm I didn't get the question, I think Athena answered better Edited September 19, 2015 by pimo

[Athena]

Can someone help me? I have no idea what I'm doing. Can someone show me the work and explain it to me?

1. A parking garage charges $1.50 for the first hour and $0.75 per hour for each additional hour or part of an hour. How many dollars will it cost Bill to park in the garage for 5 1/2 hours. 

 

2. Given f(x) = x^2+2x+1/x^2-1 , find f(2)/f(0)

 

3. Vick's Video offers two different membership plans. One plan has a $25 annual membership fee and it cost $1.50 each to rent videos. The other plan has no membership fee but it cost $3 per video rental. What is the fewest numbers of videos Sam can rent in one year for which the first plan is the least expensive.

1. It's 5 hours and 30 minutes.

So you are paying $1.50 for the first hour. You have 4 hours and 30 minutes left. You pay $0.75 for each of the remaining hours and $0.75 for the remaining 30 minutes.

 

Equation: $1.50 + $0.75 (5) = $5.25

 

2. For this you are given two x values, 2 and 0.

 

So first plug in 2 as the x and solve for it. f(2) = 2^2 + 2(2) + (1/2)^2 -1 = 4 + 4 +1/4 - 1 = 7.25

Next plug in 0 as the x and solve for it. f(0) = 0^2 + 2(0) + (1/0)^2 -1 = No answer. You can't divide a number by a zero because it becomes undefined. So this answer has no solution. Did you post the equation correctly?

 

3. So basically this is an inequality. On one side each you have to pay $3 for one video and on the other side you pay 1.50 per video BUT you also have to pay an addition $25 for a yearly membership.

 

So this would be the equation. 3x > 1.5x + 25

 

You are trying to find the fewest amount of videos you can rent where the right side of the inequality would be less than the left side.

 

Solve for x and you get 16.666677. So the answer is 17. You can check this too.

 

3(17) > 1.5 (17) + 25

51 > 25.5 + 25

51 > 50.5

 

 

If you do 16 however...

3(16) > 1.5 (16) + 25

48 > 49

 

This is wrong. So the answer must be greater than 16 therefore the fewest you can get is 17.

Edited September 19, 2015 by Athena

[BAP_STARLIGHT]

1. It's 5 hours and 30 minutes.

So you are paying $1.50 for the first hour. You have 4 hours and 30 minutes left. You pay $0.75 for each of the remaining hours and $0.75 for the remaining 30 minutes.

 

Equation: $1.50 + $0.75 (5) = $5.25

 

2. For this you are given two x values, 2 and 0.

 

So first plug in 2 as the x and solve for it. f(2) = 2^2 + 2(2) + (1/2)^2 -1 = 4 + 4 +1/4 - 1 = 7.25

Next plug in 0 as the x and solve for it. f(0) = 0^2 + 2(0) + (1/0)^2 -1 = No answer. You can't divide a number by a zero because it becomes undefined. So this answer has no solution. Did you post the equation correctly?

 

3. So basically this is an inequality. On one side each you have to pay $3 for one video and on the other side you pay 1.50 per video BUT you also have to pay an addition $25 for a yearly membership.

 

So this would be the equation. 3x > 1.5x + 25

 

You are trying to find the fewest amount of videos you can rent where the right side of the inequality would be less than the left side.

 

Solve for x and you get 16.666677. So the answer is 17. You can check this too.

 

3(17) > 1.5 (17) + 25

51 > 25.5 + 25

51 > 50.5

 

 

If you do 16 however...

3(16) > 1.5 (16) + 25

48 > 49

 

This is wrong. So the answer must be greater than 16 therefore the fewest you can get is 17.

Thank you so much! 

[Guardian of the Galaxy]

2. Given f(x) = x^2+2x+1/x^2-1 , find f(2)/f(0)

 

Just making sure for this question: is it written as A or B?

 

Edited September 20, 2015 by a232313

[BAP_STARLIGHT]

Just making sure for this question: is it written as A or B?

 

It's like this 

           x^2 + 2x +1     
f(x) = ----------------

             x^2 - 1

[Guardian of the Galaxy]

It's like this 

           x^2 + 2x +1     
f(x) = ----------------

             x^2 - 1

 

Ah, then that changes things. In order to make it clear on one line it should be written as f(x) = (x^2 + 2x +1)/(x^2 - 1)

 

Anyways, evaluating the function at x = 2 and x = 0:

 

f(2) = (2^2 + 2(2) + 1)/(2^2 - 1)

= (4 + 4 + 1)/(4 - 1)

= (9)/(3)

= 3

 

f(0) = (0^2 + 2(0) + 1)/(0^2 - 1)

= (1)/(-1)

= -1

 

f(2)/f(0) = 3/(-1)

= -3

[BAP_STARLIGHT]

Ah, then that changes things. In order to make it clear on one line it should be written as f(x) = (x^2 + 2x +1)/(x^2 - 1)

 

Anyways, evaluating the function at x = 2 and x = 0:

 

f(2) = (2^2 + 2(2) + 1)/(2^2 - 1)

= (4 + 4 + 1)/(4 - 1)

= (9)/(3)

= 3

 

f(0) = (0^2 + 2(0) + 1)/(0^2 - 1)

= (1)/(-1)

= -1

 

f(2)/f(0) = 3/(-1)

= -3

Oh my bad! Thank you!

[Mango]

A man travels 3 blocks west, 3 blocks north, and then 4 blocks east. 

(a) What is his resultant displacement?

 

 

_____ blocks at _____° counterclockwise from east.