Mango 3,020 Posted August 30, 2015 Share Posted August 30, 2015 haha no problem~ what do you have as the answer btw? Boo Link to comment Share on other sites More sharing options...
KimHeeSung 6,134 Posted August 30, 2015 Share Posted August 30, 2015 haha no problem~ what do you have as the answer btw? 1968.34264? Link to comment Share on other sites More sharing options...
pimo 4,045 Posted August 31, 2015 Share Posted August 31, 2015 1968.34264? It should be somewhere around -1.8 -302 /(5.37 x 35) multiply the 5.37 by the 35 should give you around 175 then do -302/ 175 it should equal something around -1.8 sorry for the late reply lol Boo omg youre a very scary fruit Link to comment Share on other sites More sharing options...
Mango 3,020 Posted August 31, 2015 Share Posted August 31, 2015 help Link to comment Share on other sites More sharing options...
Athena 21,718 Posted August 31, 2015 Share Posted August 31, 2015 (edited) helpAverage Velocity = Displacement / Time Displacement = V x T *Change 34 minutes into seconds Diplacement = 0.98m/s x 34(60) Displacement = 1999.2m Should be this. Edited August 31, 2015 by Athena Link to comment Share on other sites More sharing options...
Mango 3,020 Posted August 31, 2015 Share Posted August 31, 2015 Average Velocity = Displacement / Time Displacement = V x T *Change 34 minutes into seconds Diplacement = 0.98m/s x 34(60) Displacement = 1999.2m Should be this. thanks that's how I worked it n got the answer but I second guessed myself n wanted to make sure Link to comment Share on other sites More sharing options...
Mango 3,020 Posted September 4, 2015 Share Posted September 4, 2015 idgi Link to comment Share on other sites More sharing options...
Athena 21,718 Posted September 4, 2015 Share Posted September 4, 2015 idgi If it's moving at a constant velocity that means that it's not accelerating. So it's 0 m/s^2 to the right. Link to comment Share on other sites More sharing options...
pimo 4,045 Posted September 4, 2015 Share Posted September 4, 2015 idgi if the velocity is constant, then theres no acceleration right? Link to comment Share on other sites More sharing options...
Mango 3,020 Posted September 4, 2015 Share Posted September 4, 2015 If it's moving at a constant velocity that means that it's not accelerating. So it's 0 m/s^2 to the right. thanks! What kind of mean girls answer though... Link to comment Share on other sites More sharing options...
VANTE 4,595 Posted September 4, 2015 Author Share Posted September 4, 2015 thanks!What kind of mean girls answer though... lmaooooooo Link to comment Share on other sites More sharing options...
Athena 21,718 Posted September 6, 2015 Share Posted September 6, 2015 thanks! What kind of mean girls answer though... i don't get it :._.: Link to comment Share on other sites More sharing options...
Mango 3,020 Posted September 9, 2015 Share Posted September 9, 2015 part b? Link to comment Share on other sites More sharing options...
lloris 15 Posted September 9, 2015 Share Posted September 9, 2015 part b? I think you have to calculate both up and down moves to get the complete trajectory and sum the times. Up move: v = v0 - gt Considering g = 10 m/s^2 but you can also consider 9,8 or other gravity acceleration approximated values. 0 = 8 - 10t t= 0,8 s Down move: (in the down move the velocity which the ball was thrown (initial) ideally is the final) v = v0 + at 8 = 0 + 10t t = 0,8 s t = 0,8 + 0,8 = 1,6 s 3 Link to comment Share on other sites More sharing options...
Mango 3,020 Posted September 9, 2015 Share Posted September 9, 2015 I think you have to calculate both up and down moves to get the complete trajectory and sum the times. Up move: v = v0 - gt Considering g = 10 m/s^2 but you can also consider 9,8 or other gravity acceleration approximated values. 0 = 8 - 10t t= 0,8 s Down move: (in the down move the velocity which the ball was thrown (initial) ideally is the final) v = v0 + at 8 = 0 + 10t t = 0,8 s t = 0,8 + 0,8 = 1,6 s great explanation! thank you :) Link to comment Share on other sites More sharing options...
pimo 4,045 Posted September 9, 2015 Share Posted September 9, 2015 Hey everyone! I just started school lol and I'm rusty, can anyone tell me what significant digits are? And when solving a question how do I round the answer? Also were going to have a debate soon, if anyone has any opinions on either sides of the death penalty argument please share, Thanks in advance^^ Link to comment Share on other sites More sharing options...
Athena 21,718 Posted September 9, 2015 Share Posted September 9, 2015 (edited) Hey everyone! I just started school lol and I'm rusty, can anyone tell me what significant digits are? And when solving a question how do I round the answer? Also were going to have a debate soon, if anyone has any opinions on either sides of the death penalty argument please share, Thanks in advance^^ Significant digits are significant figures right? (sig fig for short) If so, it's digits that are used to make measurements look more precise? From what I remember here are the rules: 1. All non-zero numbers are significant. (i.e. 1,2,3,4,5,6) 2. Zeros are only significant when they are either: a. in between non-zero numbers (i.e in the number 4005687 the zeros are significant) b. when a decimal point is put after the final zero (i.e. 3240.) c. when there are zeros after a decimal point (i.e. 19.001) 3. If a zero is in a number without following any of the above rules it is insignificant (i.e in the number 4600 the 2 zeros are insignificant) 4. if the number if there a zeroes before a decimal point (without any other non-zero numbers before it) like this (0.00000001) those zeros are also insignificant. Using these rules you know how many sig figs are in a number...examples: a) 2400 has 2 sig figs (Rule #3) b) 2003 has 4 sig figs (Rule #2a) c) 6. has 1 sig fig (Rule #1) d) 6.00000000012 has 12 sig figs (Rule #2c) e) 0.003 has 1 sig fig (Rule #4) is this what you wanted explained? Edited September 9, 2015 by Athena 1 Link to comment Share on other sites More sharing options...
KimHeeSung 6,134 Posted September 9, 2015 Share Posted September 9, 2015 Can you help me with these.. -29.5 = 9 + 4.5(d-8) and 5 - 2.5(1.9.5x) = 18.5 Link to comment Share on other sites More sharing options...
pimo 4,045 Posted September 9, 2015 Share Posted September 9, 2015 Significant digits are significant figures right? (sig fig for short) If so, it's digits that are used to make measurements look more precise? From what I remember here are the rules: 1. All non-zero numbers are significant. (i.e. 1,2,3,4,5,6) 2. Zeros are only significant when they are either: a. in between non-zero numbers (i.e in the number 4005687 the zeros are significant) b. when a decimal point is put after the final zero (i.e. 3240.) c. when there are zeros after a decimal point (i.e. 19.001) 3. If a zero is in a number without following any of the above rules it is insignificant (i.e in the number 4600 the 2 zeros are insignificant) 4. if the number if there a zeroes before a decimal point (without any other non-zero numbers before it) like this (0.00000001) those zeros are also insignificant. Using these rules you know how many sig figs are in a number...examples: a) 2400 has 2 sig figs (Rule #3) b) 2003 has 4 sig figs (Rule #2a) c) 6. has 1 sig fig (Rule #1) d) 6.00000000012 has 12 sig figs (Rule #2c) e) 0.003 has 1 sig fig (Rule #4) is this what you wanted explained? YES THANK YOU SO MUCH :D Link to comment Share on other sites More sharing options...
pimo 4,045 Posted September 9, 2015 Share Posted September 9, 2015 (edited) Can you help me with these.. -29.5 = 9 + 4.5(d-8) and 5 - 2.5(1.9.5x) = 18.5First lets get the brackets by itself by subtracting nine from both sides -29.5 - 9= 4.5(d-8) -38.5=4.5(d-8) Divide both sides by 4.5 -38.5/4.5 = d-8 -8.333 = d-8 Then add 8 to both sides -0.333 = dd I don't get the second question, there are three decimal points lol Edited September 9, 2015 by pimo Link to comment Share on other sites More sharing options...
Carrot1202 206 Posted September 10, 2015 Share Posted September 10, 2015 (edited) For my English class I have to write an informational essay, and the topic is "How are Americans more privileged or not as privileged as citizens of other countries?" So if any of you guys has articles or websites about the topic, please give me the links. Edited September 10, 2015 by Carrot1202 Link to comment Share on other sites More sharing options...
pimo 4,045 Posted September 10, 2015 Share Posted September 10, 2015 For my English class I have to write an informational essay, and the topic is "How are Americans more privileged or not as privileged as citizens of other countries?" So if any of you guys has articles or websites about the topic, please give me the links. Try checking out the water system in the US compared to in developing nations, or water consumption rates Lol I can't research right now but some ideas u can search for are equality (gays, genders, even race),education and maybe things your government provides for you that isn't available in other places Link to comment Share on other sites More sharing options...
lloris 15 Posted September 10, 2015 Share Posted September 10, 2015 great explanation! thank you :) You're welcome :) Link to comment Share on other sites More sharing options...
Guest Posted September 12, 2015 Share Posted September 12, 2015 (edited) Significant digits are significant figures right? (sig fig for short) If so, it's digits that are used to make measurements look more precise? From what I remember here are the rules: 1. All non-zero numbers are significant. (i.e. 1,2,3,4,5,6) 2. Zeros are only significant when they are either: a. in between non-zero numbers (i.e in the number 4005687 the zeros are significant) b. when a decimal point is put after the final zero (i.e. 3240.) c. when there are zeros after a decimal point (i.e. 19.001) 3. If a zero is in a number without following any of the above rules it is insignificant (i.e in the number 4600 the 2 zeros are insignificant) 4. if the number if there a zeroes before a decimal point (without any other non-zero numbers before it) like this (0.00000001) those zeros are also insignificant. Using these rules you know how many sig figs are in a number...examples: a) 2400 has 2 sig figs (Rule #3) b) 2003 has 4 sig figs (Rule #2a) c) 6. has 1 sig fig (Rule #1) d) 6.00000000012 has 12 sig figs (Rule #2c) e) 0.003 has 1 sig fig (Rule #4) is this what you wanted explained? i would've said that 2400 has 4 significative figures but then where i live we'd never write "6." (we don't even use decimal points we use commas) because if you measure or calculate something and say that the result is 2400 then it means that you're sure that there are two zeros after your 24, or at least that's what i've always learned a rigorous way of writing it with 2 significant figures would be "2.4*10^3" i think?? i'm gonna need someone to correct me if i'm wrong i'm curious now, where are you from?? because maybe the difference comes from country conventions Edited September 12, 2015 by almasy Link to comment Share on other sites More sharing options...
pimo 4,045 Posted September 12, 2015 Share Posted September 12, 2015 i would've said that 2400 has 4 significative figures but then where i live we'd never write "6." (we don't even use decimal points we use commas) because if you measure or calculate something and say that the result is 2400 then it means that you're sure that there are two zeros after your 24, or at least that's what i've always learned a rigorous way of writing it with 2 significant figures would be "2.4*10^3" i think?? i'm gonna need someone to correct me if i'm wrong i'm curious now, where are you from?? because maybe the difference comes from country conventions I'm from Canada, my physics teacher is the same way Link to comment Share on other sites More sharing options...
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