auroras 4,218 Posted June 14, 2015 Share Posted June 14, 2015 Does anyone know how to solve this? 2log(base2)(x-3) = log(base2)(x-3) + log (base x)x^3 What is the solution of x? x is supposed to be 11. Thank you! I can donate some won if anyone would like for the help. Link to comment Share on other sites More sharing options...
Ogre Shrek 8,980 Posted June 14, 2015 Share Posted June 14, 2015 Math... Link to comment Share on other sites More sharing options...
Jiyu 2,891 Posted June 14, 2015 Share Posted June 14, 2015 sorry Link to comment Share on other sites More sharing options...
�fairytalesque� 46 Posted June 14, 2015 Share Posted June 14, 2015 2log(base2)(x-3) = log(base2)(x-3) + log (base x)x^3 log(base2)(x-3) = log (base x)x^3 (subtract log(base2)(x-3) on both sides) log(base x)x^3 = 3 because if log(base x)x^3 = n, then x^n = x^3 by definition so n=3 so log(base2)(x-3) = 3 thus 2^3 = 8 = x-3 by definition of log so x = 11 idk is that clear Link to comment Share on other sites More sharing options...
aoleu 555 Posted June 14, 2015 Share Posted June 14, 2015 Math is my trigger I thought I'd be safe here Link to comment Share on other sites More sharing options...
Thotcahontas 5,149 Posted June 14, 2015 Share Posted June 14, 2015 Math... lmaooooooooooooooooooooooo why am I laughing so hard Link to comment Share on other sites More sharing options...
Jam 785 Posted June 14, 2015 Share Posted June 14, 2015 2log(base2)(x-3) = log(base2)(x-3) + log(basex)(x^3) 2log(base2)(x-3) = log(base2)(x-3) + 3 log(base2)[(x-3)^2] = log(base2)(x-3) + log(base2)(2^3) log(base2)[(x-3)^2] = log(base2)[(x-3)(2^3) (x-3)^2 = (x-3)(2^3) x-3 = 2^3 x-3 = 8 x = 11 Link to comment Share on other sites More sharing options...
auroras 4,218 Posted June 14, 2015 Author Share Posted June 14, 2015 2log(base2)(x-3) = log(base2)(x-3) + log (base x)x^3 log(base2)(x-3) = log (base x)x^3 (subtract log(base2)(x-3) on both sides) log(base x)x^3 = 3 because if log(base x)x^3 = n, then x^n = x^3 by definition so n=3 so log(base2)(x-3) = 3 thus 2^3 = 8 = x-3 by definition of log so x = 11 idk is that clear 2log(base2)(x-3) = log(base2)(x-3) + log(basex)(x^3) 2log(base2)(x-3) = log(base2)(x-3) + 3 log(base2)[(x-3)^2] = log(base2)(x-3) + log(base2)(2^3) log(base2)[(x-3)^2] = log(base2)[(x-3)(2^3) (x-3)^2 = (x-3)(2^3) x-3 = 2^3 x-3 = 8 x = 11 Thank you so much! Link to comment Share on other sites More sharing options...
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