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Math Help pt.2 (Integrals and graphing)


Camila Cabello

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i hate graphing so don't wanna do q4

 

for 5, you set y = 4x^2 -7

-> dy/dx = 8x

-> it becomes integral of (2dy*y^5) = 1/3y^6+c

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Sorry, I'm taking an online course and its a bit difficult to self learn

 

tumblr_nm5lwyulWt1t04eewo1_540.png

5.

Let u=4x2-7

du=8x dx

dx= du/ (8x)

 

(Then you substitute du in for dx)

 

2 integral u5 du

(Then you antidifferentiate it)

2(u6/6) +C= u6/3 +C= (4x2-7)6/3 + C

Do you have an answer sheet? not sure if I got the right answer

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