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College Algebra Help! (its only one question)


xLeeChaex

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1. open your algebra book

2. do your own fucking homework

 

Dude i did my own homework for ur damn information i just want to see how everybody else solves it because the way the book gave it was confusing in this case i solved it already u damn fucker

I already know its no solution for this question all already so dont talk shit

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Dude i did my own homework for ur damn information i just want to see how everybody else solves it because the way the book gave it was confusing in this case i solved it already u damn fucker

I already know its no solution for this question all already so dont talk shit

/dead

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   3x           6              12


--------- +  ---------  =   ------------


 x + 2         x           x^2 +2x


 


 


Multiply the (x+2) in the first denominator by 'x'. By doing this you need to also multiply the numerator which is 3x by x.


 


Multiply the x  in the second denominator by 'x+2'. By doing this you need to also multiply the numerator which is 6 by x+2.


 


End result is:


 


    3x^2       +   6x + 12   =      12


---------------      --------------    -------------


 x^2 + 2x        x^2 + 2x       x^2 +2x


 


 


Is that all? or do you want to solve for x too?


 


 


If you are solving for x.


 


Subtract 12 from both sides (set equal to zero) and you get:


 


 3x^2 + 6x


----------------  = 0


  x^2 + 2x


 


Simplify:


 


  3x (x+2)


----------------  = 0


   x (x+2)


 


Everything cancels out and 3 cannot equal 0. So there are no solutions.


 


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Equations are easier if there are no fractions, I think you'll agree. So we'll start by eliminating the fractions. The asiest way to eliminate the fractions in an equation is to multiply both sides by the Lowest Common Denominator (LCD). And to find the LCD we need to factor the denominators:
plot-formula.mpl?expression=3x%2F%281%28
The LCD is the product of all the different factors. So the LCD here is:
(x+2)x
This is what we will multiply both sides by:
plot-formula.mpl?expression=%28x%2B2%29x
On the left side we need to use the Distributive Property:
plot-formula.mpl?expression=%28x%2B2%29x
Now we can cancel:
plot-formula.mpl?expression=cross%28%28x
leaving:
plot-formula.mpl?expression=x%283x%29+%2
which simplifies as follows:
plot-formula.mpl?expression=3x%5E2+%2B+6
Without the fractions, this is a very simple equation to solve. It is a quadratic equation so we want one side equal to zero. So subtract 12 from each side:
plot-formula.mpl?expression=3x%5E2+%2B+6

 

Now we factor:
3x(x + 2) = 0
From the Zero Product Property we know that this product can be zero only if one of the factors is zero. So:
3x = 0 or x+2 = 0
Solving these we get:
x = 0 or x = -2

With equations where the variable is in one or more denominators, it is important to check your answers. We must make sure no denominators are zero! Always check with the original equation.
plot-formula.mpl?expression=3x%2F%28x%2B
Checking x = 0:
plot-formula.mpl?expression=3%280%29%2F%
which simplifies to:
plot-formula.mpl?expression=0%2F2+%2B+6%
As you can see, two of the denominators are zero. For this reason we must reject x = 0 as a solution. (If even only one denominator was zero we would still reject the solution.)

Checking x = -2:
plot-formula.mpl?expression=3%28-2%29%2F
which simplifies to:
plot-formula.mpl?expression=%28-6%29%2F%
Again we get zero denominators! We must reject this solution, too.

So there are no solutions to your equation!

cr  :imstupid:
 
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He doesnt know wtf he is talking about really lmfao

I already solved it and got the answer, but the way the book explained it was wtf

Eyyy and you even got two members to help. Solid!

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Equations are easier if there are no fractions, I think you'll agree. So we'll start by eliminating the fractions. The asiest way to eliminate the fractions in an equation is to multiply both sides by the Lowest Common Denominator (LCD). And to find the LCD we need to factor the denominators:

plot-formula.mpl?expression=3x%2F%281%28

The LCD is the product of all the different factors. So the LCD here is:

(x+2)x

This is what we will multiply both sides by:

plot-formula.mpl?expression=%28x%2B2%29x

On the left side we need to use the Distributive Property:

plot-formula.mpl?expression=%28x%2B2%29x

Now we can cancel:

plot-formula.mpl?expression=cross%28%28x

leaving:

plot-formula.mpl?expression=x%283x%29+%2

which simplifies as follows:

plot-formula.mpl?expression=3x%5E2+%2B+6

Without the fractions, this is a very simple equation to solve. It is a quadratic equation so we want one side equal to zero. So subtract 12 from each side:

plot-formula.mpl?expression=3x%5E2+%2B+6

 

 

Now we factor:

3x(x + 2) = 0

From the Zero Product Property we know that this product can be zero only if one of the factors is zero. So:

3x = 0 or x+2 = 0

Solving these we get:

x = 0 or x = -2

 

With equations where the variable is in one or more denominators, it is important to check your answers. We must make sure no denominators are zero! Always check with the original equation.

plot-formula.mpl?expression=3x%2F%28x%2B

Checking x = 0:

plot-formula.mpl?expression=3%280%29%2F%

which simplifies to:

plot-formula.mpl?expression=0%2F2+%2B+6%

As you can see, two of the denominators are zero. For this reason we must reject x = 0 as a solution. (If even only one denominator was zero we would still reject the solution.)

 

Checking x = -2:

plot-formula.mpl?expression=3%28-2%29%2F

which simplifies to:

plot-formula.mpl?expression=%28-6%29%2F%

Again we get zero denominators! We must reject this solution, too.

 

So there are no solutions to your equation!

 

cr  :imstupid: 

 

 

Would u care to explain where they got the one from?? Like the one from here??

plot-formula.mpl?expression=3x%2F%281%28

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