xLeeChaex 46 Posted November 23, 2014 Share Posted November 23, 2014 Write the slope intercept form of the equation of the line described through:( 3, -3), parallel to y=-1 And this is how i solved it y-(-3)=-1(x-3) y+3=-x+3 -3 -3 y=-x But my teacher marked it wrong saying its y=-3 which i dont get why is that the answer lol Can u guys explain lol Link to comment Share on other sites More sharing options...
abra 40,910 Posted November 23, 2014 Share Posted November 23, 2014 What's a slope intercept form? Link to comment Share on other sites More sharing options...
karutamral 647 Posted November 23, 2014 Share Posted November 23, 2014 y = -1 is a horizontal line, so find a horizontal line that goes through (3,-3) , so.... y = -3. And... it's slope is not -1. It's 0. -1 is the y-intercept. Link to comment Share on other sites More sharing options...
elmo 2,760 Posted November 23, 2014 Share Posted November 23, 2014 y=-3 the line is horizontal and passes through the y point -3 Link to comment Share on other sites More sharing options...
Ron Swanson 6,677 Posted November 23, 2014 Share Posted November 23, 2014 What's a slope intercept form? y=mx+b Link to comment Share on other sites More sharing options...
abra 40,910 Posted November 23, 2014 Share Posted November 23, 2014 y=mx+b So just a standard straight line/linear function? Link to comment Share on other sites More sharing options...
Ron Swanson 6,677 Posted November 23, 2014 Share Posted November 23, 2014 So just a standard straight line/linear function? yeah basically. Link to comment Share on other sites More sharing options...
.............. 821 Posted November 23, 2014 Share Posted November 23, 2014 y = -1 is a horizontal line, so find a horizontal line that goes through (3,-3) , so.... y = -3. And... it's slope is not -1. It's 0. -1 is the y-intercept. ^^^ It becomes: y-(-3)=0(x-3) y+3=0 y=-3 Link to comment Share on other sites More sharing options...
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