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CALC HW HELP 25K WON REWARD PER QUESTION


potaeto

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Hi. I'm offering 25,000 won per each question answered and explained to me CORRECTLY. If a question has more than one blank or box, i will award double. You can answer as many as you like.

 

Although there is a time limit. You have until 11:59pm PST. Thank you.

 

1) Determine the equation of the tangent line at the indicated domain value.

f(t) = 8t; t = 1
y(t) = ____________
 
2) Answer the question by using the Exponential Rule or the Logarithmic Rule, as appropriate.

Based on data from 1994 to 2001, the quarterly tuition of a resident student at Green River Community College may be modeled by
E(t) = 430.6(1.042)t dollars

where t is the number of years since 1994.†

How quickly was quarterly tuition increasing in 2002? (Round your answer to the nearest cent.)
____________dollars per year

 

3) Answer the question by using the Exponential Rule or the Logarithmic rule, as appropriate.

Based on data from the 1990-1991 through the 2002-2003 school year, the total school expenditure, in billions of dollars, may be modeled by

T(E) = −2915 + 366.6 ln E
where E is the per pupil expenditure in dollars.†

Calculate
T'(2000).
(Round your answer to four decimal places.)
T'(2000) = _________________

billion dollars in total school expenditure per dollar of per pupil expenditure

 

4)Use implicit differentiation to find

dy dx .
2x2 + y2 = 8
dy dx  = _________________


Evaluate the derivative function at the designated point. (If an answer is undefined, enter UNDEFINED.)
(2, 0)
At (2, 0),
dy dx

 = _______________

 

5) Use implicit differentiation to find

dy dx .
x2− y2 = 65
dy dx

 = __________

 

 

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Thanks  :)  :)  :)  I was just in tutoring for the past 4 hours and we still weren't able to reach these questions so i have to get to this option since my teacher is HORRIBLE at teaching. :>_>:

 

Oh my goodness I feel your pain.  :omgwtf: 

My professor is absolutely horrible as well (she literally makes mistakes all the time, and my classmates have to correct it for her). I'm either going to have to teach myself or get a tutor. 

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Now, I haven't had calculus for two years, but I did get a five on both AB/BC, so maybe I still remember a little. 

 

For implicit differentiation, you want to make it become dy/dx, so I think it's 

 

2x^2 + y^2 = 8 

 

y^2 = 8 - 2x^2

 

2y(dy) = -4x(dx)

dy = -4xdx/2y

dy/dx = -4x/2y 

 

Right? It's probably wrong; it's been so long since I've done it. 

 

But, I think it's basically you need to remember to do the chain rule, take the derivatives correctly, and make sue dy is over dx, right? IDK

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Now, I haven't had calculus for two years, but I did get a five on both AB/BC, so maybe I still remember a little. 

 

For implicit differentiation, you want to make it become dy/dx, so I think it's 

 

2x^2 + y^2 = 8 

 

y^2 = 8 - 2x^2

 

2y(dy) = -4x(dx)

dy = -4xdx/2y

dy/dx = -4x/2y 

 

Right? It's probably wrong; it's been so long since I've done it. 

 

But, I think it's basically you need to remember to do the chain rule, take the derivatives correctly, and make sue dy is over dx, right? IDK

Sorry, #4 was answered earlier but you can try the other questions!!

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#1

F(t) = 8^t   t=1

F(1) = 8^1 = 8   so the point is (1,8)

F’(t) = 8^(t)ln(8)

F’(1) = 8^(1)ln(8) = 8ln(8) = m

y-8=8ln(8)(t-1)

y-8 = 8(t)ln(8) – 8ln(8)

y(t) = 8(t)ln(8) – 8ln(8) + 8 --> (you could add the 8ln(8) and the 8 but that would give you a decimal and that is usually frowned upon, instead by leaving it like I left it, you can get a more accurate answer when you evaluate for any value of t.)

Is it right?

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#1

F(t) = 8^t   t=1

F(1) = 8^1 = 8   so the point is (1,8)

F’(t) = 8^(t)ln(8)

F’(1) = 8^(1)ln(8) = 8ln(8) = m

y-8=8ln(8)(t-1)

y-8 = 8(t)ln(8) – 8ln(8)

y(t) = 8(t)ln(8) – 8ln(8) + 8 --> (you could add the 8ln(8) and the 8 but that would give you a decimal and that is usually frowned upon, instead by leaving it like I left it, you can get a more accurate answer when you evaluate for any value of t.)

 

Is it right?

YES CORRECT!!! 25K more to you~~

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BRUH

8(t)ln(8) – 8ln(8) + 8

= 16.64t - 8.64

which was what I posted before. But it would probs be better to leave it in exact form anyway (i just got lazy and didnt wanna type all that up)

hmm.. i typed it into the website the same exact form you submitted your answer and it counted it as incorrect. :/ This website is stupid and only accepts things in certain forms.. sorry

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#2

E(t) = 430.6(1.042)t dollars

They are asking you for the slope E’(t).

E’(t) = (430.6)((1.042^t)ln(1.042))

Since t=the number of years SINCE 1994 (as in not counting 1994), then the value of t would be 2002-1994= 8 = t

E’(8) = (430.6)((1.042^8)ln(1.042)) = 24.6

Is it right?

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#2

E(t) = 430.6(1.042)t dollars

They are asking you for the slope E’(t).

E’(t) = (430.6)((1.042^t)ln(1.042))

Since t=the number of years SINCE 1994 (as in not counting 1994), then the value of t would be 2002-1994= 8 = t

E’(8) = (430.6)((1.042^8)ln(1.042)) = 24.6

Is it right?

CORRECT!!! damn girl you're smart :) 25K more won~~

 

 

ALL QUESTIONS HAVE BEEN ANSWERED. THERE IS NO MORE TO REWARD. THANKS TO ALL THE GENIUSES WHO PARTICIPATED I APPRECIATE IT!!

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